- Summaries (4)
Adrian Monk is a brilliant San Francisco detective, whose obsessive compulsive disorder just happens to get in the way.
After the unsolved murder of his wife, Adrian Monk develops obsessive-compulsive disorder, which includes his terror of germs and contamination. His condition costs him his job as a prominent homicide detective in the San Francisco Police Department, but he continues to solve crimes with the help of his assistant and his former boss.
Former police detective Adrian Monk (Tony Shalhoub) has suffered from intensified obsessive- compulsive disorder and a variety of phobias since the murder of his wife, Trudy, in 1997. Despite his photographic memory and his amazing ability to piece tiny clues together, he is now on psychiatric leave from the San Francisco Police Department. Aided by his friend and practical nurse, Sharona Fleming (Bitty Schram), Monk works as a freelance detective/consultant, hoping to convince his former boss, Captain Stottlemeyer (Ted Levine), to allow him to return to the force. Stottlemeyer wavers between admiration for Monk and annoyance at his eccentricities. Moreover, he harbors serious doubts about the wisdom of allowing Monk to carry a gun. Stottlemeyer's second-in-command, Lieutenant Disher (Jason Gray-Stanford), also has his doubts about Monk but seems to be developing a reluctant admiration for the "defective detective."
Detective Adrian Monk used to have a minor case of obsessive-compulsive disorder. Then, the murder of his wife and his inability to solve the case exacerbated his condition to the point where he finds it impossible to function in society without assistance. He hires Sharona Fleming, a nurse and single mother, as his personal assistant, as well as his Watson for when he investigates cases the police can't solve to pay the bills. After three seasons Sharona got tired of the frustrating job and remarried her husband. Monk's new assistant is Natalie Teeger, whose loss of her own partner allows her a deeper bond with him than Sharona could ever have.
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